The vapor pressure of a pure liquid at 25 degree celcius is 100mm Hg. Calculate the relative lowering of vapor pressure if the mole fraction of solvent in solution is 0.8
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the mole fraction of solvent = 0.8
therefore mole fraction of solute = 1- 0.8 = 9.2
since p^0 - p^s / P^0 = mole fraction of solute
hence relative lowering of VP = 9.2
therefore mole fraction of solute = 1- 0.8 = 9.2
since p^0 - p^s / P^0 = mole fraction of solute
hence relative lowering of VP = 9.2
Answered by
13
their has been slight mistake in the above answer it is supposed to be 0.2 not 9.2..thank you
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