Question

The vapor pressures of the two liquids A and B are 0.6 bar and 0.2 bar respectively. How many mole fractions of fluid A will there be in the ideal solution formed from these two liquids when the partial pressure of both the liquids becomes equal?
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Answer 1

Answer:

0.75

Explanation:

Pa = 0.6 bar

Pb = 0.2 bar

ATQ :- P°a = P°b (Since, Partial vp equal)

Pa = P°a × Xa. -----(eq 1)

Pb = P°b × Xb

P°b = Pb/Xb

P°a = Pb/Xb (becoz Equal)

Put this in eq 1

Pa = Pb/Xb × Xa

0.6 = 0.2/( 1-Xa) × Xa (Xa + Xb = 1)

3 - 3Xa = Xa

Xa = 3/4

Xa = 0.75

ANS