the vapour density of a gas is 11.2 calculate the volume occupied by 11.2 gram of the gas at ntp
Answers
Answered by
1
Molecular mass of the gas = 2×2× Vapour density of the gas
Molecular Mass = 2×11.2=22.4g/m2×11.2=22.4g/m
22.4 g of the gas = 1 mol of the gas
11.2 g of the gas = (1×11.2)22.4(1×11.2)22.4 = 0.5 mole of gas
1 mole of gas = 22.4 L of gas
∴∴ 0.5 mole of gas = (22.4×0.5)(22.4×0.5) = 11.2 L of gas
Molecular Mass = 2×11.2=22.4g/m2×11.2=22.4g/m
22.4 g of the gas = 1 mol of the gas
11.2 g of the gas = (1×11.2)22.4(1×11.2)22.4 = 0.5 mole of gas
1 mole of gas = 22.4 L of gas
∴∴ 0.5 mole of gas = (22.4×0.5)(22.4×0.5) = 11.2 L of gas
Similar questions