Question

the vapour density of a gas X is 8. what is the volume of 24 gm X in STP?

Answer 1

molecular mass =2×Vapour density
so molecular mass =2×8 = 16 g.m
16 gm of gas occupy 22.4 ltr at S.T.P
24 g.m will occupy =( 22.4/16)×24=33.6 ltr
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Answer 2

we know ,
molecular weight =2 x vapour density

so,
molecular wt of X = 2 x 8 = 16 gm

mole = given wt /molecular wt
= 24/16 = 3/2 = 1.5

1 mole of volume of gas at STP = 22.4 L
so, 1.5 mole of given gas volume =22.4 x 1.5 = 33.6 L

hence ,
33.6 L volume of gas