Question

the vapour density of a mixture containing equal number of moles of methane and ethane at stp is​

Answer 1

Answer:

8:15

Explanation:

as we know that .,m.m=2*vd

Answer 2

The vapour density of a mixture containing an equal number of moles of methane and ethane at stp is​ 11.5

Explanation:

• Vapour density is defined as the density of a vapour, which is in relation to that of hydrogen.

• It may also be defined as the mass of a certain volume of a substance divided by the mass of the same volume of hydrogen.

$Vapour density =$  $\frac{mass of n molecules of gas}{mass of n molecules of hydrogen}$

The molar mass of the mixture will be

$Mmix=$ $\frac{nMolar mass of CH4+nMolarmass of C2H6}{n+n}$

$Mmix=$$\frac{n(16+30)}{2n}$

$Mmix=$$\frac{46}{2}$

$Mmix=23$

$Vapour density=$ $\frac{Mmix}{2}$

$Vapour density =$$\frac{23}{2}$$=11.5$

vapour density of a mixture is 11.5

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