What is the vakue of sex^2A-tan^2A??
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Answer:
●Sec²A-Tan²A
→1/cos²A-sin²A/cos²A
→(1-sin²A) /Cos²A {1-sin²A= cos²A}
→cos²A/Cos²A
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Answered by
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Answer:
sec square theta - tan square theta= 1
sec 2A²-tan2A²=1....
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