Question

the vapour density of a volatile chloride of a metal is 59.5 and equivalent mass of the metal is 24 the atomic mass of the element will be​

Answer 1

Molecular formula of the compound is MCl2, where M is the divalent cation.

Vapour density (D) = Molecular mass (M) /2

So molar mass of the compound = 2 x 59.5 = 119

Equivalent mass (E) = molar mass (M) / (number of cation x valency)

Number of cation = 1, and valency of the cation =2

So, E = 119 / (1x2) = 59.5

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