The vapour pressure of a solvent is 80 mm. On
Sol adding a non-volatile solute its drops to 60 mm Hg.
The mole fraction of the solute in the solution is
Answers
Answered by
0
Step-by-step explanation:
Using Raoults law for lowering of vapour pressure.We get
P
o
P
o
−P
=x
2
putting,Values of actual and lowered vapour pressure we get
0.8
0.8−0.6
=x
2
where x
2
is the mole fraction
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Answer:
The vapour pressure of pure liquid solvent A is 0.80atm when a non-volatile solute B is added to the solvent its vapours pressure falls to 0.60atm. Mole fraction of solute B in the solution is:
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