Question

The vapour pressure of benzene is 200mm.The lowering of vapour pressure of 0.2 molal solution is

Answer 1

Answer:

The lowering of the vapour pressure, Δp, measured is . 3.12 x $10^{-6}$ mm.

Explanation:

From the above question, they have Given,

The vapour pressure of benzene is 200mm.The lowering of vapour pressure of 0.2.

We need to find the molal solution:

The vapour pressure of benzene,

$p^{0}$ = 200nm

    = 200 x $10^{-6}$ mm

    = 2 x $10^{-4}$mm

The molality of the solution,

m = 0.2 mol

The lowering of the vapour pressure,

We need to find Δp

Now,

From the equation given below, we can find out the lowering of the vapour pressure:

Here,

Δp = Lowering of the vapour pressure

$p^{0}$ = Vapour pressure

m = Molality

M = The molar mass of benzene = 78g/mol

After putting the given values in the equation, we get:

Δp =  31.2 x $10^{-7}$

Hence, the lowering of the vapour pressure, Δp = .3.12 x $10^{-6}$mm.

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