the vapour pressure of pure benzene at an certain temperature is 0.850 bar a non valatile non electrolyte solid weighing 0.5 g when added to 39.0 of benzene molar mass 789 mol vapour pressure of solutions then is 0.845bar what is the molar mass of the solid substance
Answers
Answered by
3
Explanation:
ANSWER
p 0p 0 −p = W 1M 2W 2M 1p 0
=0.850bar= vapour pressure of pure benzene.
p=0.845bar= vapour pressure of solution.
W 1=39g= mass of benzene
W 2 =78g= mass of solute
M 1=78g/mol= Molar mass of benzene.
M 2= Molar mass of solute.
0.850bar
0.850bar−0.845bar= 39g×M 20.5g×78g/mol
M 2 =170g/mol
Similar questions