Question

The vapour pressure of pure water at 25 c is 30 mm. the vapour pressure of 10 percent glucose solution at 25 c

Answer 1

the vapour pressure of 10 percent glucose solution at 25 c 35mm I hope it Help you

Answer 2

Answer : The vapor pressure of solution is, 29.67 mm

Explanation:

As the relative lowering of vapor pressure is directly proportional to the amount of dissolved solute.

The formula for relative lowering of vapor pressure will be,

$\frac{p^o-p_s}{p^o}=\frac{w_2M_1}{w_1M_2}$

where,

$p^o$ = vapor pressure of pure solvent  (water) = 30 mm

$p_s$ = vapor pressure of solution = ?

$w_2$ = mass of solute  (glucose) = 10 g in 100 g of solution

$w_1$ = mass of solvent  = (water) = (100-10) = 90 g

$M_1$ = molar mass of solvent (water) = 18 g/mole

$M_2$ = molar mass of solute (glucose) = 180 g/mole

Now put all the given values in this formula ,we get the vapor pressure of the solution.

$\frac{30-p_s}{30}=\frac{10\times 18}{90\times 180}$

$p_s=29.67 mm$

Therefore, the vapor pressure of solution is, 29.67 mm.