The vapour pressure of pure water is 40 mm. If a nonvolatile solute is added to it, vapour pressure falls vapour by 4 mm. Hence, molality of solution is:
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Relative lowering in vapour pressure
(Po – P)/Po = 4/40 = 0.1 = xs
So xo = 0.9
m = 1000*xs/xo*Mo = 1000*0.1/0.9*18 = 6.17 m
Hope it cleras....................
gopalreddybella:
the options are 5.55 m,3.0864 m,1.546 m,0.722 m
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Answer: 6.17 m
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