Math, asked by suzuya, 1 year ago

the variable 'x' is inversely proportional to 'y'. If 'x' increase by p% then what % will y differ?

Answers

Answered by Anjali1110

y will get reduced by p%.

suzuya: can you elaborate the answer?

Anjali1110: umm see... x is inversely proportional to y. so when x increases y decreases. when x gets doubled, y will get halved. similarly when x will increase by p%, y will decrease by p%. hope it helped :)

suzuya: thank you ^_^

Anjali1110: you're welcome :)

Answered by Jayparth

x is proportional to y
Therefore,    X $\alpha$ 1/y
i.e. X =k 1/Y

Now , X + p% =1/Y +p%

therefore, X+ p% = 1+ Yp%/Y

Now,    p% = 1 + yp%/y - x
Adding by y on both sides of equation,

y+p% = 1+ yp%/y -x + y
Considering RHS,
   = 1/Y + Yp%/Y -X/Y .....[ Divinding By Y Throughout equation]

   = 1/X+Xp% .....[By componendo and dividendo]

Jayparth: Thus, corresponding increment in Y is 1/X + Xp%

Jayparth: And Sorry,My apologies for mistakenly pressing the send tab before finishing whole of the solution! It was just a part of misdeed!

suzuya: hey thank you so much! this was all i needed^_^

Jayparth: And thanks from mine sides too, for taking my fault in consideration. <3

suzuya: ah i never mind such things ^^

Anjali1110: that was a very cool answer i must say kudos

Anjali1110: :)

Jayparth: Thanks For your compliments! :)

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