The variance of the first 50 even natural numbers is
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Hi dear ...
Here is U Answer......could u plsss mark it as brainlist answer plsss ...plsss...
Variance =∑xi2N−(x¯¯¯)2∑xi2N−(x¯)2
σ2=22+42....100250σ2=22+42....100250
=(2+4+....100)250=(2+4+....100)250
=4(12+22+32....+1002)50−(512)=4(12+22+32....+1002)50−(512)
=4(50×51×10150×6)−(51)2=4(50×51×10150×6)−(51)2
=3434−2601=3434−2601
σ2=833
Hope this answer helpful for u
Here is U Answer......could u plsss mark it as brainlist answer plsss ...plsss...
Variance =∑xi2N−(x¯¯¯)2∑xi2N−(x¯)2
σ2=22+42....100250σ2=22+42....100250
=(2+4+....100)250=(2+4+....100)250
=4(12+22+32....+1002)50−(512)=4(12+22+32....+1002)50−(512)
=4(50×51×10150×6)−(51)2=4(50×51×10150×6)−(51)2
=3434−2601=3434−2601
σ2=833
Hope this answer helpful for u
SrinathReddy1:
bro plss mark it as brainlist please bro
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