The variation of acceleration due to gravity of earth as
one moves away from earth's center to surface of
earth is given by (Where R is radius of earth)
[NCERT Pg. 191]
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Answer:
Given
a
2
=13 and a
5
=25
We know that
a
n
=a+(n−1)d
∴a
2
=a+(2−1)d
⇒13=a+(2−1)d
⇒a+d=13 ...(i)
and a
5
=a+(5−1)d
⇒25=a+4d
⇒a+4d=25 ...(ii)
Now, subtracting (i) from (ii), we get
3d=12
⇒d=4
Now a+d=13 [from (i)]
⇒a=9
Hence, a
7
=a+6d=9+6(4)
⇒a
7
=33
Explanation:
फर्स्ट सेशन ऑफ क्वेश्चन ऑफ फिजिक्स असोमैक्स दिस क्वेश्चन इज नॉट
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sathya304:
excuse me i can't understand anything
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