Physics, asked by sathya304, 3 months ago

The variation of acceleration due to gravity of earth as
one moves away from earth's center to surface of
earth is given by (Where R is radius of earth)
[NCERT Pg. 191]


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Answers

Answered by xxALONEKINGxx
2

Answer:

Given

a

2

=13 and a

5

=25

We know that

a

n

=a+(n−1)d

∴a

2

=a+(2−1)d

⇒13=a+(2−1)d

⇒a+d=13 ...(i)

and a

5

=a+(5−1)d

⇒25=a+4d

⇒a+4d=25 ...(ii)

Now, subtracting (i) from (ii), we get

3d=12

⇒d=4

Now a+d=13 [from (i)]

⇒a=9

Hence, a

7

=a+6d=9+6(4)

⇒a

7

=33

Explanation:

फर्स्ट सेशन ऑफ क्वेश्चन ऑफ फिजिक्स असोमैक्स दिस क्वेश्चन इज नॉट

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sathya304: excuse me i can't understand anything
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