the variation of force acting on a particle along the x axis is shown in the figure.Find the work done by the force during displacement x=0 to x=25m.
Answers
Answered by
2
Area under the F-x graph gives the work done by the force in that displacement.
(a) : Work done (from x = -2 m to x=0),
W= − 1/2×10×2=−10 J
(b) : Work done (from x = 0 m to x=2 m),
W= -1/2×10×2=10 J
Answered by
0
Answer:-10 joules
Explanation:
From x=−2 mtox= 0m, displacement of the particle is along positive x-direction while force acting on the particle is along negative x-direction. Therefore, work done is negative and given by the area under F-x graph.
∴W=−
2
1
(2)(10)=−10J
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