Physics, asked by Sneha144, 1 year ago

The variation of horizontal and vertical distances with time are given by y=8t-4.9t²,x=6t with MKS units.then the velocity of projection is ?

Answers

Answered by saro12
0

Answer:

i guess velocity of projection is 6

Answered by mandalasaivaraprasad
0

Answer:

10 m/s^2

Explanation:

For a projectile projected at an angle θ

x and y coordinates are given as:

x=vcosθt=6t

y=vsinθt−1/2 g t^2=8t-4.9 t^2

⇒  On comparing,

vcosθ=6

vsinθ=8⇒v=10 m/s

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