The variation of horizontal and vertical distances with time are given by y=8t-4.9t²,x=6t with MKS units.then the velocity of projection is ?
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Answer:
i guess velocity of projection is 6
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Answer:
10 m/s^2
Explanation:
For a projectile projected at an angle θ
x and y coordinates are given as:
x=vcosθt=6t
y=vsinθt−1/2 g t^2=8t-4.9 t^2
⇒ On comparing,
vcosθ=6
vsinθ=8⇒v=10 m/s
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