The variation of velocity of a particle moving along a straight line in a certain
time interval is shown below. What is the distance travel during acceleration?
question number 5
please help!
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S = area under graph = 35 m
from B onwards velocity is constant
so S after B is 3x10 = 30... before b find the area of tat small triangle = 0.5x10x1=5 Thus S = 5m + 30m= 35m this must be new technique for u but in v vs t graph, displacement=area under graph
from B onwards velocity is constant
so S after B is 3x10 = 30... before b find the area of tat small triangle = 0.5x10x1=5 Thus S = 5m + 30m= 35m this must be new technique for u but in v vs t graph, displacement=area under graph
Brainergy:
Okay
Just a sec
from B onwards v is constant... so S after B is 3x10 = 30...
before b find the area of tat small triangle = 0.5x10x1=5
Thus S = 5m + 30m= 35m
this must be new technique for u
but in v vs t graph, displacement=area under graph
Fine?
I beg u please mark my answer brainliest!!!! pleasee!!!
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