Question

the difference between the ages of two brothers today is 4 years. five years ago, the ratio of their ages was 5:7. Find the ages of the younger brother

Answer 1

Let the first brother age=x

second brother=x+4

BEFORE 5 years
Ages were x-5,x+4+(-5)
=x-5,x-1

Given ratio=5:7

x-5/x-1=5/7

7(x-5)=5(x-1)

7x-35=5x-5

7x-5x=35-5=30

x=15 years

hence the younger brother age=15

Answer 2

Answer:

hence the younger brother age is 15