the difference between the ages of two brothers today is 4 years. five years ago, the ratio of their ages was 5:7. Find the ages of the younger brother
Answers
Answered by
23
Let the first brother age=x
second brother=x+4
BEFORE 5 years
Ages were x-5,x+4+(-5)
=x-5,x-1
Given ratio=5:7
x-5/x-1=5/7
7(x-5)=5(x-1)
7x-35=5x-5
7x-5x=35-5=30
x=15 years
hence the younger brother age=15
second brother=x+4
BEFORE 5 years
Ages were x-5,x+4+(-5)
=x-5,x-1
Given ratio=5:7
x-5/x-1=5/7
7(x-5)=5(x-1)
7x-35=5x-5
7x-5x=35-5=30
x=15 years
hence the younger brother age=15
Answered by
1
Answer:
hence the younger brother age is 15
Similar questions