if cosx +secx=2 then cos^2x+sec^2x equal to what
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Answered by
6
cosx + secx =2
Now, cos²x+sec²x
= (cosx+secx)²-2cosx.secx
=2²-2
=4-2
=2
we know that cosx*secx=1
Now, cos²x+sec²x
= (cosx+secx)²-2cosx.secx
=2²-2
=4-2
=2
we know that cosx*secx=1
Answered by
4
square on both sides
(cosx+secx)²=2²
cos²x+sec²x+2cosxsecx=4
cos²x+sec²x=4-cosxsecx
cos²x+sec²x=4-2cosx*1/cost
cos²x+sec²x=4-2
cos²x+sec²x=2
Therefore cos²x+sec²x=2
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(cosx+secx)²=2²
cos²x+sec²x+2cosxsecx=4
cos²x+sec²x=4-cosxsecx
cos²x+sec²x=4-2cosx*1/cost
cos²x+sec²x=4-2
cos²x+sec²x=2
Therefore cos²x+sec²x=2
Plz mark me as brainliest
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