Question

the vector A has a magnitude of 5 unit, B has a magnitude of 6 unit and the cross product of A and B has a magnitude of 15 unit . find the angle between A and B ​

Answer 1

Answer:

Let angle between A and B = x

A×B = A B sinx

15 = 5× 6 sinx

sinx = 15/30

sin x = 1/2

therefore x = 30°

Explanation:

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Answer 2

Given:

The magnitude of vector a = 5 unit

The magnitude of vector B = 6 unit

The magnitude of the cross product of A and B = 15

To find:

The angle between A and B.

Solution:

We know that the formula for the cross product can be written as:

A×B = |A| |B| sinα

Where α is the angle between vectors A and B.

On substituting the values in the equation, we get:

15 = 5×6 sinα

On further simplifying, we get:

15 = 30 sinα

On further simplifying, we get:

sin α = 1/2

From this equation, we can conclude that:

α = 30°

Thus, the angle between vectors A and B will be 30°.