Question

The vector equation of the plane through the line of intersection of the planes x + y + z = 1 and 2x + 3y + 4z = 5 which is perpendicular to the plane x – y + z = 0 is:
(A) ⃗r × (î – kˆ) + 2 = 0
(B) ⃗r.(î – kˆ) – 2 = 0
(C) ⃗r.(î – kˆ) + 2 = 0
(D) ⃗x × (î – kˆ) + 2 = 0

Answer 1

The vector equation of the plane through the line of intersection of the planes x + y + z = 1 and 2x + 3y + 4z = 5 which is perpendicular to the plane x – y + z = 0 is:

(A) ⃗r × (î – kˆ) + 2 = 0✅❤

(B) ⃗r.(î – kˆ) – 2 = 0

(C) ⃗r.(î – kˆ) + 2 = 0

(D) ⃗x × (î – kˆ) + 2 = 0

Answer 2

Answer:

$\huge\boxed{\fcolorbox{black}{pink}{Hi mate!}}$

The vector equation of the plane through the line of intersection of the planes x + y + z = 1 and 2x + 3y + 4z = 5 which is perpendicular to the plane x – y + z = 0 is:

(A) ⃗r × (î – kˆ) + 2 = 0✔

(B) ⃗r.(î – kˆ) – 2 = 0

(C) ⃗r.(î – kˆ) + 2 = 0

(D) ⃗x × (î – kˆ) + 2 = 0