Physics, asked by shams87, 1 year ago

the velocity at the maximum height of projectile is √3/ 2 in initial velocity of projectile u its range of the horizontal plane is

Answers

Answered by ktgupta12344
2
at maximum height the velocity of a projectile is only in X direction so cos theta equals to cos 30 where theta equals to 30/u
R=U^2 SIN2 THETA/ 2G
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