Physics, asked by ylniarb8713, 11 months ago

The velocity of a 4.0-n hockey puck,sliding across a level ice surface,decreases at the rate of 0.61m/s2 . The coefficient of kinetic friction between the puck and ice is:

Answers

Answered by aristocles
1

Answer:

Coefficient of the friction on the ice surface is given as

\mu = 0.062

Explanation:

As we know that the deceleration of the hockey puck is given as

a = -0.61 m/s^2

now we know that force of friction on the hockey puck is given as

F_f = \mu mg

now the deceleration due to friction on it given as

a = \mu g

now we have

\mu g = 0.61

so we have

\mu = \frac{0.61}{9.81}

\mu = 0.062

#Learn

Topic : Friction force

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