Question

The velocity of a ball changes from 77m/s to 44m/s in 11s calculate the acceleration.With step

Answer 1

Given,v=77m/s

u=44m/s

time=11seconds

as we know,a=v-u/t

77-44/11

33/11=3m/s^2

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Answer 2

Answer:

a = -3 $ms^{-2}$

Explanation:

u = 77

v = 11

t = 11

a = $\frac{v-u}{t}$

a = $\frac{44-77}{11}$

a = $\frac{-33}{11}$

a = -3 $ms^{-2}$