The velocity of a block of mass 6kg as a function of time is v=5t^2+3t+2 m/s . The force associated with the block at time t= 2s is,
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The velocity of a block of mass 6kg as a function of time is v = (5t² + 3t + 2) m/s
we know,
“ acceleration is the rate of change of velocity with respect to time.”
so, differentiating given function with respect to time.
we get acceleration, a = dv/dt = 10t + 3
at t = 2sec , acceleration, a = 10 × 2 + 3 = 23 m/s²
from Newton's 2nd law,
F = ma
= 6kg × 23m/s²
= 138 N
hence, The force associated with the block at time t = 2s is 138N
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