Question

the velocity of a body moving vertically up is 49m/sat half the maximum height . The height to which it could further rise up is?

Answer 1

Initial velocity is 49 m per sec and final velocity is 0 n the gravitational force is 9.8 m per sec sq so by using the formula v^2-u^2=2gh, we can find the answer.
Hope it helps u dear

Answer 2

$\huge\underline\mathfrak{Answer}$

GIVEN

velocity at half of maximum height = 49m/s

TO FIND

The height it could further rise

We know that,

velocity at maximum height = 0

{v}^{2} - {u}^{2} = -2gh(for body projected vertically up)

Substituting

u = 49 & v = 0 & g = 9.8,

{0}^2 - {49}^2 =- 2(9.8)(s)

- 2401 = -19.6s

s = -2401/-19.6

s = 122.5 m

Hope it helps...