Question

The velocity of a body of mass 100g increases from 2m/s to 6m/s when a force acts on it for 2 sec. a. What is the momentum before the force acts? b. What is the momentum after the force acts? c. What is the gain in momentum per second? d. What is the value of the force?

pls, answer ASAP. I'll mark as brainliest

Answer 1

Answer:

given, m= 100 g or 0.1 kg

u = 2 m/s v= 6 m/s t = 2 sec

a.initial mommentum means before applying force

p = mu = 0.1× 2 = 0.2 kgm/s

b.final mommentum means after applying force

P = mv = 0.1× 6 = 0.6 kgm/s

c. gain of mommentum per second

that is 0.2 kgm/s

d. F = ma = 0.1 × v-u/t = 0.1 × 2 =0.2 N

Answer 2

Answer:

Answer as follows:

Explanation:

a) initial momentum = mu = 0.1*2 =0.2kgm/s

b) final momentum = mv = 0.1*6 = 0.6kgm/s

c) gain in momentum per sec = (0.6-0.2)/2

                                                   = 0.2 kgm/s^2

d) F = m(v-u)/t

       = 0.1(6-2)/2

        = 0.2 N