Physics, asked by jithinsalish, 8 months ago

the velocity of a body which has fallen freely under gravity varies as phgq where g is the accceleration due to gravity at the place and h is the height through which the body has fallen determine the values of p and q

Answers

Answered by Mrunalinisuryawanshi
2

Answer:

down is earth gravitational

Answered by parkjimin1
13

Answer:

p = 1/2 and q = 1/2

explanation : A body is falling freely under gravity. so, initial velocity of body will be zero. let v is the velocity of body when it falls h from the initial position.

using formula, v² = u² + 2as

here, a = -g , u = 0 and s = -h

then, v² = 0 + 2(-g)(-h)

or, v² = 2gh

or, v = √(2gh) = √2(gh)½

here it is clear that velocity of a body has fallen freely under gravity varies as (gh)½.

on comparing with g^ph^q ,

we get p = 1/2 and q = 1/2

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