the velocity of a body which has fallen freely under gravity varies as phgq where g is the accceleration due to gravity at the place and h is the height through which the body has fallen determine the values of p and q
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down is earth gravitational
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Answer:
p = 1/2 and q = 1/2
explanation : A body is falling freely under gravity. so, initial velocity of body will be zero. let v is the velocity of body when it falls h from the initial position.
using formula, v² = u² + 2as
here, a = -g , u = 0 and s = -h
then, v² = 0 + 2(-g)(-h)
or, v² = 2gh
or, v = √(2gh) = √2(gh)½
here it is clear that velocity of a body has fallen freely under gravity varies as (gh)½.
on comparing with g^ph^q ,
we get p = 1/2 and q = 1/2
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