Question

The velocity of a bullet moving with initial velocity 300 m/second becomes 400 m/sec. Find the distance covered by the bullet during this period.
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Answer 1

Answer:

Initial Velocity(u) = 300 m/s

Final Velocity(v) = 400 m/s

To Find :-

Distance covered(h)

Formula Required :-

v^2-u^2=2ghv

2

−u

2

=2gh

g = 10 m/s^2

Solution :-

(400)^2-(300)^2=2\times 10\times h(400)

2

−(300)

2

=2×10×h

160000 - 90000 = 20\times h160000−90000=20×h

70000=20\times h70000=20×h

h=\dfrac{70000}{20}h=

20

70000

h = 3500

Distance Covered = 3500 m

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Explained:

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