The velocity of a cae increased uniformly from 5m/s to 10m/s when it travels 50m .Find the acceleration of the car
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Answer:
final velocity=10m/s
initial velocity=5m/s
distance traveled=50m
Applying 3rd equation of motion
v²-u²=2as
10²-5²=2*a*50
100-25=100a
75=100a
a=75÷100=0.75m/s2
Answer is 0.75m/s²
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