Question

the velocity of a car at 10:50 a.m. is 60 km per hour and at 10:52 a.m. it is 80 km per hour assuming constant acceleration in the given period find its value ​

Answer 1

$\huge\underline\blue{\sf Answer:}$

$\large\red{\boxed{\sf Acceleration (a)=0.46\:m/{s}^{2}}}$

$\huge\underline\blue{\sf Solution:}$

$\large\underline\pink{\sf Given: }$

• Initial velocity (u) = 60km/h

Convert it into m/s

u = 60 × 5/18

u = 16.6 m/s

• Final Velocity (v) = 80km/h

Convert it into m/s

v = 80 × 5/18

v = 22.2 m/s

• Time (t) = 120 seconds

$\large\underline\pink{\sf To\:Find: }$

• Acceleration (a) = ?

━━━━━━━━━━━━━━━━━━━━━━━━━

$\large{\boxed{\sf Acceleration (a)={\frac{u-v}{t}}}}$

$\large\implies{\sf {\frac{22.2-16.6}{120}}}$

$\large\implies{\sf a =0.46m/{s}^{2}}$

$\large\red{\boxed{\sf Acceleration (a)=0.46\:m/{s}^{2}}}$