Question

The velocity of a car at 10.50 am is 60 km/h and at 10.52 am it is 80km/h. assuming constant acceleration in the given period, find its value.

How do you do this

Answer 1

u=60km/h=50/3=16.66m/s
v=80km/h=200/9=22.22m/s
t=120s
a=v-u/t
a=(200-150)/9/120
=50/9/120
a=0.046

Answer 2

Answer:

u=60km/h=50/3=16.66m/s

v-80km/h=200/9=22.22m/s

t=120s

a=v-u/t

a=(200-150)/9/120

=50/9/120

a=0.046