The velocity of a car increase from 54 km/hr to 72 km/hr. How much is the work done if the mass of the car is 1500 kg ?(Ans. : 131250 J).Solve the example.
Answers
Answered by
5
The velocity of the car in m/s for two phases is:
{1}54*5/18 ----> 15m/s
{2}72*5/18 ---->20m/s.
the work done in accelerating the car=1/2*1500*(20^2–15^2)
=750*(400–225)
=750*175J
=131250J
Hope it helps u.
{1}54*5/18 ----> 15m/s
{2}72*5/18 ---->20m/s.
the work done in accelerating the car=1/2*1500*(20^2–15^2)
=750*(400–225)
=750*175J
=131250J
Hope it helps u.
Answered by
2
Answer:
131250 J
Explanation:
Kinetic energy = (1/2)mV²
54 k/Hr = 54* 1000/3600 = 15 m/s
Kinetic energy of the car at 54 km/Hr = (1/2) * 1500 * 15²
= 168750 J
72 k/Hr = 72* 1000/3600 = 20 m/s
Kinetic energy of the car at 54 km/Hr = (1/2) * 1500 * 20²
= 300000 J
Work done = 300000 J - 168750 = 131250 J
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