Question

The velocity of a free falling body just before hitting the ground is 9.8ms-1, the height
through which it fall be:​

Answer 1

Answer:

v = √2gh

9.8 = /2 * 9.8 * h

9.8 * 9.8 = 2 * 9.8 * h

h = 4.9 m

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Answer 2

Answer:

The height through which it will fall is 4.9 m.

Explanation:

Given,

velocity near the ground = V = 9.8 m/s

To find,

From what height the body is being fallen (H)

We know that from conservation of energy:

decrease in potential energy = increase in kinetic energy

i.e. $MgH = \frac{1}{2} MV^2$

⇒ $H = \frac{V^2}{2g}$

Now we substitute the values of V = 9.8 m/s and g = 9.8 $ms^{-2}$

We get:

$H = \frac{(9.8ms^{-1})^2}{2\times9.8ms^{-2}}$

H = 4.9 m

Therefore, the height through which it will fall is 4.9 m.

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