Question

The velocity of a moving body increases from 10 m/s to 5 m/s in 5 seconds. Calculate its acceleration.

Answer 1

Explanation:

given::

1. final velocity = 10m/s

2. initial velocity = 5m/s

3. time taken = 5 seconds

to find::

acceleration of the particle

solution::

we know that,

the rate of change of velocity is called as acceleration

$\boxed{\blue{\tt a=\dfrac{v-u}{t} }}$

applying concepts::

putting value of V , U and T in the above equation we get,

$\tt acc = \dfrac{(10)-(5)}{5}$

$\tt acc = \dfrac{5}{5}$

$\tt acc = 1$

the unit of acceleration would be :

metre - metre / sec²

===> m/s²

therefore,

the value of acceleration would be 1m/s²

hope this helps you out!!

Answer 2

Answer:

1. final velocity = 10m/s

2. initial velocity = 5m/s

3. time taken = 5 seconds

to find::

acceleration of the particle

solution::

we know that,

the rate of change of velocity is called as acceleration

\boxed{\blue{\tt a=\dfrac{v-u}{t} }}

a=

t

v−u

Explanation:

putting value of V , U and T in the above equation we get,

\tt acc = \dfrac{(10)-(5)}{5}acc=

5

(10)−(5)

\tt acc = \dfrac{5}{5}acc=

5

5

\tt acc = 1acc=1

the unit of acceleration would be :

metre - metre / sec²

===> m/s²putting value of V , U and T in the above equation we get,

\tt acc = \dfrac{(10)-(5)}{5}acc=

5

(10)−(5)

\tt acc = \dfrac{5}{5}acc=

5

5

\tt acc = 1acc=1

the unit of acceleration would be :

metre - metre / sec²

===> m/s²

therefore,

the value of acceleration would be 1m/s²

hope this helps you out!!

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