Question

The velocity of a moving object changes from 20m/s to 60/s in 10s. Calculate its acceleration?​

Answer 1

Answer:

$\boxed{\mathfrak{Acceleration \ (a) = 4 \ m/s^2}}$

Given:

Initial velocity (u) = 20 m/s

Final velocity (v) = 60 m/s

Time taken (t) = 10 s

To Find:

Acceleration (a)

Explanation:

$\sf From \ 1^{st} \ equation \ of \ motion: \\ \boxed{ \bold{v = u + at}}$

Substituting value of v, u and t in the equation:

$\sf \implies 60 = 20 + a(10) \\ \\ \sf \implies 60 - 20 = 10a \\ \\ \sf \implies 40 = 10a \\ \\ \sf \implies 10a = 40 \\ \\ \sf \implies a = \frac{4 \cancel{0}}{ \cancel{10}} \\ \\ \sf \implies a = 4 \: m/s^2$

$\therefore$

Acceleration (a) = 4 m/s²

Answer 2

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$\bigstar \: \underline{ \large \mathtt{ \pink{ \bf Question : }}}$

• The velocity of a moving object changes from 20m/s to 60/s in 10s. Calculate its acceleration?

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$\bigstar \: \underline{ \large \mathtt{ \orange{ \bf Given: }}}$

• initial velocity = 20 m /s
• final velocity = 60 m /s
• time taken = 10 seconds

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$\bigstar \: \underline{ \large \mathtt{ \green{ \bf To \: find : }}}$

• acceleration

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$\bigstar \: \underline{ \large \mathtt{ \purple{ \bf Solution : }}}$

By applying the first equation of motion ,

$\implies \large \boxed{\mathtt{v = u + at}}$

here ,

• v = final velocity
• u = initial velocity
• a = acceleration
• t = time taken

$\rightarrow \mathtt{a = \dfrac{v - u}{t} }$

Now substituting the given values in the above equation we get ,

$\rightarrow \mathtt{a = \dfrac{60 - 20}{10} }$

$\rightarrow \mathtt{a = \dfrac{40}{10} }$

$\rightarrow \mathtt{ \red{a = 4 \dfrac{m}{ {s}^{2} } }}$

The acceleration of the body is 4 m / s ²

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$\bigstar \: \underline{ \large \mathtt{ \bf Other \: formulas: }}$

second equation of motion ,

$\implies \large \boxed{\mathtt{s = ut + \dfrac{1}{2} a {t}^{2} }}$

third equation of motion

$\implies \large \boxed{\mathtt{ {v}^{2} = {u}^{2} + 2as }}$

distance covered by the body in nth second ,

$\implies \large \boxed{\mathtt{s_n = u + \dfrac{a}{2} (2n - 1)}}$