Question

The velocity of a moving particle is related to displace-
mentas,
v^2 = 2 ks where k is constant.
The displacement suffered in time 't' will be:
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Answer 1

Answer:

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Answer 2

Answer:

The displacement in time t , s=$\dfrac{kt^2}{2}$

Explanation:

Given:

The variation of velocity with displacement ,$v^2=2ks$

Using the method of calculus we know that

$v=\dfrac{ds}{dt}$

$v=\sqrt{2ks}\\\dfrac{ds}{dt}=\sqrt{2ks}$

Integrating both sides we have

$\int \dfrac{ds}{\sqrt{s}}=\int \sqrt{2k}\ dt\\2\sqrt{s}= \sqrt{2k}t$

Squaring both sides we have

$s=\dfrac{kt^2}{2}$