the velocity of a particle in SHM at the instant when it is 0.6 cm away from the mean position is 4 centimetre per second . If the amplitude of vibration is 1 cm then its velocity at the instant when it is 0.8 CM away from the mean position is (in cm/s)?
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The velocity of the particle at that instant is
V2 = 3 m/s
Explanation:
V = √ωA^2−x^2
V1 = √ωA^2−x1^2
4 cm/s = √ 1 - (0.6)^2
ω = 4 / √ 1 - (0.36
ω = 4 / √ 0.64
ω = 4/0.8
V2 = √ωA^2−x2^2
V2 = 4/0.8 x √ 1 - (0.6)^2
V2 = 4/0.8 x √ 0.36
V2 = 4/0.8 x 0.6
V2 = 1/0.2 x 0.6
V2 = 3 m/s
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