Question

The velocity of a particle is v=(i+j-k)m. A force of 10
$10 \sqrt{3}$
3 N is applied in the direction of velocity.
Find the applied force in vector form.​

Answer 1

Answer:

The direction vector of velocity

= (i+j-k)/√(1²+1²+1²)

= i/√3 +j/√3 -k/√3

now force has magnitude of 10√3 and the direction vector is same as of velocity

-)so force vector is (10√3)( i/√3 +j/√3 -k/√3) = 10i+10j-10k