the velocity of a particle moving along x axis is given as v=x2-5x+4 find the magnitude of the acceleration of the particle when the velocity of the particle is zero
Answers
Answered by
1
Explanation Given velocity
v=x2−5x+4
Acceleration a≡dvdt
∴a=ddt(x2−5x+4)
⇒a=(2xdxdt−5dxdt)
We also know that dxdt≡v
⇒a=(2x−5)v
at v=0 above equation becomes
a=0
v=x2−5x+4
Acceleration a≡dvdt
∴a=ddt(x2−5x+4)
⇒a=(2xdxdt−5dxdt)
We also know that dxdt≡v
⇒a=(2x−5)v
at v=0 above equation becomes
a=0
Similar questions