Question

.The velocity of a particle moving in positive x-axis according to relation v V4x. If at t = 0 particle is at x = 0, then the velocity and acceleration at t = 2s are given as (1) 4 m/s, 4 m/s2 (2) 2 m/s, 2 m/s2 (3) 2 m/s, 4 m/s2 (4) 4 m/s, 2 m/s2​

Answer 1

Explanation:

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Answer 2

Answer:

(4) 4 m/s, 2 m/s2

Explanation:

v= √4x = 2√x

dv/dx = 2 x 1/2 x^1/2-1

= 1/√x

a= v dv/dx =2√x x 1/√x

=2 m/s^2

Now s = ut +1/2at^2

Given that u=0

S = 1/2 x 2x2^2

= 4m

v^2 - u^2 = 2as

V= √2as = √2x2x4 = 4m/s

Hence v=4m/s and a=2m/s^2