The velocity of a particle moving in positive x-axis
is according to relation v =√4x. If at t = 0
particle is at x = 0, then the velocity and
acceleration at t = 2s are given as
(1) 4 m/s, 4 m/s2
(2) 2 m/s, 2 m/s2
(3) 2 m/s, 4 m/s2
(4) 4 m/s, 2 m/s2
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Answer:
Explanation:
v=√4x = 2√x
dv/dx = 2 × 1/2 x^1/2-1
= 1/√x
a= v dv/dx =2√x × 1/√x
= 2 m/s^2
Now s = ut +1/2at^2
Given that u=0
s = 1/2 × 2 × 2^2
= 4 m
v^2 - u^2 =2as
v = √2as = √2×2×4 = 4m/s
Hence v=4m/s and a=2m/s^2
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