Question

The velocity of a particle moving in positive x-axis
is according to relation v =√4x. If at t = 0
particle is at x = 0, then the velocity and
acceleration at t = 2s are given as
(1) 4 m/s, 4 m/s2
(2) 2 m/s, 2 m/s2
(3) 2 m/s, 4 m/s2
(4) 4 m/s, 2 m/s2
​

Answer 1

Answer:

Explanation:

v=√4x = 2√x

dv/dx = 2 × 1/2 x^1/2-1

= 1/√x

a= v dv/dx =2√x × 1/√x

= 2 m/s^2

Now s = ut +1/2at^2

Given that u=0

s = 1/2 × 2 × 2^2

= 4 m

v^2 - u^2 =2as

v = √2as = √2×2×4 = 4m/s

Hence v=4m/s and a=2m/s^2