Question

The velocity of a particle varies with time according to the relation v = at^2+ bt + c, where v is in ms-1and t in second. Find the dimensions of a, b and c

Answer 1

Answer:

[a]=LT^-3

[b]=LT^-2

[c]=LT^-1

Explanation:

[V]=[a][t]^2+[b][t]+[c]

Separate dimensions of v with at^2 , bt and c

{L=[dimensions of length] and T=[dimensions of time]}

[V]=LT^-1

[V]=[a][t]^2

LT^-1=[a]*T^2

[a]=LT^-3

[V]=[b][t]

LT^-1=[b]T

[b]=LT^-2

[V]=[c]

[V]=LT^-1

[c]=LT^-1

Hope its helpful