The velocity of a particule is v = 2t + cos (2t). When t = k the acceleration is 0. Show that k = pi/4?
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Given, v = 2t+cos(2t)
So ,
acceleration,a = dv/Dr
a=d (2t+cos(2t ))/dt
a=2-2sin(2t)
according to question,if t=k;a =0
therefore ,2-2sin(2k)=0
sin (2k) =1
sin (2k) =sin (pi/2)
2k=pi/2
k=pi/4
So ,
acceleration,a = dv/Dr
a=d (2t+cos(2t ))/dt
a=2-2sin(2t)
according to question,if t=k;a =0
therefore ,2-2sin(2k)=0
sin (2k) =1
sin (2k) =sin (pi/2)
2k=pi/2
k=pi/4
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