Question

The velocity of a point moving in straight line changes according to the equation V=(3t^2+2t+1) m/s. Find the
acceleration of the point at start of first second.
(A) zero
(B) 1m/s2
(C)2 m/s2
(D) none of these
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Answer 1

c is the answer 2m/s^2 because differentiation of velocity gives acceleration. so, after it substitute t=0 in the equation you will get the answer.