The velocity of a small ball of mass m and density d1 when dropped in a container filled with glycerine becomes constants after sometime. What is the viscous force acting on the ball ?
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Answer: Md1gd2
Mg(1−d2d1)
M(d1+d2)g
Md1d2
Answer :
B
Solution :
Since ball gains the constant velocity.
Therefore, net force on the ball = zero.
⇒ Weight of the ball = Buoyancy force + Viscous force (Fv)
⇒Mg=Md1×d2×g+Fv
∴Fv=Mg(1−d2d1)
Explanation:
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