Question

The velocity of a train increases uniformly from 20km/h to 60km/hr in 20 seconds.Calculate the acceleration of the train in m/s2​

Answer 1

Question:-

• The velocity of a train increases uniformly from 20kmph to 60kmph in 20 seconds.Calculate the acceleration of the train in m/s²

To Find:-

• Find the acceleration of the train.

Solution:-

Given ,

• Initial velocity of train is 5.5 m/s

• Final velocity of train is 16.67 m/s

• Time taken to increase the speed is 20 sec.

Here ,

Formula to be Used:-

• v = u + at

Substitute in the equation:-

$\dashrightarrow\sf \: v = u + at$

$\dashrightarrow\sf \: 16.67 = 5.55 + 20t$

$\dashrightarrow\sf \: 20t = 16.67 - 5.55$

$\dashrightarrow\sf \: 20t = 11.12$

$\dashrightarrow\sf \: t = \cancel\dfrac { 11.12 } { 20 }$

$\dashrightarrow\sf \: t = 0.5 \: { m/s }^{ 2 }$

Hence,

• Acceleration is 0.5 m/s²

Answer 2

Answer ❣️------

Question:-

The velocity of a train increases uniformly from 20kmph to 60kmph in 20 seconds.Calculate the acceleration of the train in m/s²

To Find:-

Find the acceleration of the train.

Solution:-

Given ,

Initial velocity of train is 5.5 m/s

Final velocity of train is 16.67 m/s

Time taken to increase the speed is 20 sec.

Here ,

Formula to be Used:-

v = u + at

Substitute in the equation:-

\dashrightarrow\sf \: v = u + at⇢v=u+at

\dashrightarrow\sf \: 16.67 = 5.55 + 20t⇢16.67=5.55+20t

\dashrightarrow\sf \: 20t = 16.67 - 5.55⇢20t=16.67−5.55

\dashrightarrow\sf \: 20t = 11.12⇢20t=11.12

\dashrightarrow\sf \: t = \cancel\dfrac { 11.12 } { 20 }⇢t=

20

11.12

\dashrightarrow\sf \: t = 0.5 \: { m/s }^{ 2 }⇢t=0.5m/s

2

Hence,

Acceleration is 0.5 m/s²