Biology, asked by prabhavati09, 9 months ago

The velocity of an electron with deBroglie wavelength of 1x10?nmis
(A) 7.2x105cm/ sec
(B) 72x10 cm/ sec
(C) 7.2x104cm/sec
(D) 3.6x10 cm/sec​

Answers

Answered by rocky200216
2

Given,

de-broglie wavelength

= 1×10²nanometer

= 10^-5 centimeter .

we have,

de-broglie wavelength= h/(m × v)

=> 10^-5 = (6.62×10^-34)/{(9.1×10^-31) v}

=> v = (6.62×10^-34)/{(9.1×10^-31)(10^-5)}

=> v = 7.2 × 10^5 centimeter/second .

So, Correct answer is (B) .

Hope it's helpful to you.

Please mark as Brainlist answer.

Answered by Anonymous
0

Given,

de-broglie wavelength

= 1×10²nanometer

= 10^-5 centimeter .

we have,

de-broglie wavelength= h/(m × v)

=> 10^-5 = (6.62×10^-34)/{(9.1×10^-31) v}

=> v = (6.62×10^-34)/{(9.1×10^-31)(10^-5)}

=> v = 7.2 × 10^5 centimeter/second .

The velocity of an electron with deBroglie wavelength of 1x10?nmis

(A) 7.2x105cm/ sec

(B) 72x10 cm/ sec [✓]

(C) 7.2x104cm/sec

(D) 3.6x10 cm/sec

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