The velocity of an electron with deBroglie wavelength of 1x10?nmis
(A) 7.2x105cm/ sec
(B) 72x10 cm/ sec
(C) 7.2x104cm/sec
(D) 3.6x10 cm/sec
Answers
Answered by
2
Given,
de-broglie wavelength
= 1×10²nanometer
= 10^-5 centimeter .
we have,
de-broglie wavelength= h/(m × v)
=> 10^-5 = (6.62×10^-34)/{(9.1×10^-31) v}
=> v = (6.62×10^-34)/{(9.1×10^-31)(10^-5)}
=> v = 7.2 × 10^5 centimeter/second .
So, Correct answer is (B) .
Hope it's helpful to you.
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Answered by
0
Given,
de-broglie wavelength
= 1×10²nanometer
= 10^-5 centimeter .
we have,
de-broglie wavelength= h/(m × v)
=> 10^-5 = (6.62×10^-34)/{(9.1×10^-31) v}
=> v = (6.62×10^-34)/{(9.1×10^-31)(10^-5)}
=> v = 7.2 × 10^5 centimeter/second .
The velocity of an electron with deBroglie wavelength of 1x10?nmis
(A) 7.2x105cm/ sec
(B) 72x10 cm/ sec [✓]
(C) 7.2x104cm/sec
(D) 3.6x10 cm/sec
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