Question

. The velocity of an object increases at a constant rate from 20 m/s to 50 m/s in 10 s .Find the acceleration. *

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Answer 1

Explanation:

Acceleration a=

Acceleration a= t

Acceleration a= tv−u

Acceleration a= tv−u

Acceleration a= tv−u =

Acceleration a= tv−u = 10s

Acceleration a= tv−u = 10s50 ms

Acceleration a= tv−u = 10s50 ms −1

Acceleration a= tv−u = 10s50 ms −1 −20 ms

Acceleration a= tv−u = 10s50 ms −1 −20 ms −1

Acceleration a= tv−u = 10s50 ms −1 −20 ms −1

Acceleration a= tv−u = 10s50 ms −1 −20 ms −1

Acceleration a= tv−u = 10s50 ms −1 −20 ms −1

Acceleration a= tv−u = 10s50 ms −1 −20 ms −1 or a=

Acceleration a= tv−u = 10s50 ms −1 −20 ms −1 or a= 10s

Acceleration a= tv−u = 10s50 ms −1 −20 ms −1 or a= 10s30 ms

Acceleration a= tv−u = 10s50 ms −1 −20 ms −1 or a= 10s30 ms −1

Acceleration a= tv−u = 10s50 ms −1 −20 ms −1 or a= 10s30 ms −1

Acceleration a= tv−u = 10s50 ms −1 −20 ms −1 or a= 10s30 ms −1

Acceleration a= tv−u = 10s50 ms −1 −20 ms −1 or a= 10s30 ms −1

Acceleration a= tv−u = 10s50 ms −1 −20 ms −1 or a= 10s30 ms −1 =3 ms

Acceleration a= tv−u = 10s50 ms −1 −20 ms −1 or a= 10s30 ms −1 =3 ms −2

Answer 2

GIVEN

• Initial Velocity , u = 20m/s
• Final Velocity , v = 50m/s
• Time , t = 10s

TO FIND

• Acceleration

SOLUTION

From 1st eqn. of motion, we have

• v = u + at
• 50 = 20 + a × 10
• 10a = 50-20 m/s²
• a = 30/10 m/s²
• a = 3m/s²

Acceleration of the object is 3m/s²